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Tuesday 8 January 2019

Apparent Weight In Lift

Apparent weight:

" When a body moves or accelerate in the opposite direction of gravity or  along the direction of gravity then the body weight appears to change, this resulted weight of the body is known as Apparent weight. "

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➡The gravitational force nothing but the force of attraction exerted by the Earth on the body of mass m.


➡Weight of the body is referred as the gravitational force acting on a body.


W = mg 


Apparent weight of a body in lift:


➡3 conditions are considered for the Apparent weight of a body in lift.


➡1. When the lift is at rest( acceleration is zero/ uniform velocity)


➡2. When the lift accelerates upwards


➡3. When the lift accelerates downwards


1. When the lift is at rest:

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➡Consider an object in a lift which is at rest or moving upwards and downwards with uniform velocity.


➡Since the lift is at rest or at uniform velocity, its acceleration will be zero.


➡Therefore the Apparent weight of an object is equal to its actual weight.


W1 = R = mg 


2. When the lift accelerates upwards:

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➡Consider an object of mass m in a lift which is moving upwards with uniform acceleration a


➡Since it is moving upwards it's floor pushes the object with the same acceleration.


➡Therefore excess force appears to occur on the object which is not the floor.


➡The Apparent weight will be greater than the actual weight.


W1 = m(g + a)


3. When did lift accelerates downwards:

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➡a. When the lift move downwards with acceleration a which is less than the acceleration due to gravity g then the object accelerates downloads by taking a part of force of gravity as its acceleration to move downwards.


➡Therefore Apparent weight will be less than that of the actual weight.


W1 = m(g - a)


➡b. When the lift moves downward with an acceleration greater than that of acceleration due to gravity.


➡Then the Apparent weight of the object will be negative.


➡The object will be staying at the ceiling of the lift.


W1 = m(g - a) = negative.


➡c. When the lift is free falling, then the acceleration of the lift is equal to acceleration due to gravity (a = g).


➡At free falling, the object will be experiencing a state of weightlessness.


W1 = m(g -a) = m(g - g) = 0

 

2 comments:

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